2x=75x+26x^2

Solution for 2x=75x+26x^2 equation:

2x=75x+26x^2

We move all terms to the left:

2x-(75x+26x^2)=0

We get rid of parentheses

-26x^2-75x+2x=0

We add all the numbers together, and all the variables

-26x^2-73x=0

a = -26; b = -73; c = 0;
Δ = b2-4ac
Δ = -732-4·(-26)·0
Δ = 5329
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5329}=73$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-73)-73}{2*-26}=\frac{0}{-52}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-73)+73}{2*-26}=\frac{146}{-52}
=-2+21/26
$